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(C) To determine the number of optically active compounds,we check for the presence of chiral centers and the absence of a plane of symmetry $(POS)$ o

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$1$

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(C) To determine the number of optically active compounds,we check for the presence of chiral centers and the absence of a plane of symmetry $(POS)$ or center of symmetry $(COS)$.$1$. $2,3$-butanediol (first structure): The structure shown is the meso form (due to a plane of symmetry),so it is optically inactive.$2$. $2,3,4$-hexanetriol (second structure): This molecule has chiral centers at $C2, C3,$ and $C4$. It does not possess a plane of symmetry or center of symmetry,making it optically active.$3$. $1$-butanol $(CH_3-CH_2-CH_2-CH_2-OH)$: No chiral center,optically inactive.$4$. $2$-chlorobutane $(CH_3-CH_2-CHCl-CH_3)$: This molecule has a chiral center at $C2$. It is optically active.$5$. $1$-chlorobutane $(CH_3-CH_2-CH_2-CH_2-Cl)$: No chiral center,optically inactive.$6$. $1$-chloro-$3$-methylbutane $((CH_3)_2CH-CH_2-CH_2-Cl)$: No chiral center,optically inactive.Thus,there are $2$ optically active compounds in the given list.

Total number of optically active compounds from the following is $......$

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